Jumat, 03 Juni 2011

c++ dan masalah IF

The if-else Statement

The if statement controls conditional branching.
if ( expression )
   statement1
[else
   statement2]
If the value of expression is nonzero, statement1 is executed. If the optional else is present, statement2 is executed if the value of expression is zero. expression must be of arithmetic or pointer type, or it must be of a class type that defines an unambiguous conversion to an arithmetic or pointer type. (For information about conversions, see Standard Conversions.)
In both forms of the if statement, expression, which can have any value except a structure, is evaluated, including all side effects. Control passes from the if statement to the next statement in the program unless one of the statements contains a break, continue, or goto.
The else clause of an if...else statement is associated with the closest previous if statement that does not have a corresponding else statement.
For example:
// if_esle_statement.cpp
#include <stdio.h>
int main()
{
   int x = 0;
   if( 1 )         // if statement #1
   {
      if( !x )      // if statement #2
         printf("!x\n");
      else                  //paired with if statement #2
         printf("x\n");
   }

The if-else Statement

The if statement controls conditional branching.
if ( expression )
   statement1
[else
   statement2]
If the value of expression is nonzero, statement1 is executed. If the optional else is present, statement2 is executed if the value of expression is zero. expression must be of arithmetic or pointer type, or it must be of a class type that defines an unambiguous conversion to an arithmetic or pointer type. (For information about conversions, see Standard Conversions.)
In both forms of the if statement, expression, which can have any value except a structure, is evaluated, including all side effects. Control passes from the if statement to the next statement in the program unless one of the statements contains a break, continue, or goto.
The else clause of an if...else statement is associated with the closest previous if statement that does not have a corresponding else statement.
For example:
// if_esle_statement.cpp
#include <stdio.h>
int main()
{
   int x = 0;
   if( 1 )         // if statement #1
   {
      if( !x )      // if statement #2
         printf("!x\n");
      else                  //paired with if statement #2
         printf("x\n");
   }

The if-else Statement

The if statement controls conditional branching.
if ( expression )
   statement1
[else
   statement2]
If the value of expression is nonzero, statement1 is executed. If the optional else is present, statement2 is executed if the value of expression is zero. expression must be of arithmetic or pointer type, or it must be of a class type that defines an unambiguous conversion to an arithmetic or pointer type. (For information about conversions, see Standard Conversions.)
In both forms of the if statement, expression, which can have any value except a structure, is evaluated, including all side effects. Control passes from the if statement to the next statement in the program unless one of the statements contains a break, continue, or goto.
The else clause of an if...else statement is associated with the closest previous if statement that does not have a corresponding else statement.
For example:
// if_esle_statement.cpp
#include <stdio.h>
int main()
{
   int x = 0;
   if( 1 )         // if statement #1
   {
      if( !x )      // if statement #2
         printf("!x\n");
      else                  //paired with if statement #2
         printf("x\n");
   }
}
}
}

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